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Papessa [141]
3 years ago
12

Identify the type of reaction described in the sentence below. then, write a chemical equation. be sure to specify the states of

all chemicals and balance the equation. phosphoric reacts with oxygen gas, forming solid tetraphosphorus decoxide. (use p as the formula for phosphoric, not p4.
Chemistry
1 answer:
natulia [17]3 years ago
6 0

Answer : The type of reaction described in the sentence is Synthesis or Combination

Explanation :

The balanced equation for the reaction between Phosphorous and Oxygen gas can be written as

4P (s) + 5O_{2} (g) ------>  P_{4} O_{10}  (s)

From the above equation we can see that there are two different reactants ( P and O₂ ) which are combining with each other to give a single product.

This type of reaction is known as Combination or Synthesis.

A general form of Synthesis reaction is given below.

A + B ---->  AB

Here we can conclude that a synthesis / combination reaction is the one where 2 or more reactants combine together to give only one product .

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How many molecules are in 0.79 moles of NH4?
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14

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Which particle j j Thomson discovered
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A methanol-water mixture is to be flash distilled at 1 atm. If the feed is 25 mole %methanol, what are the liquid and vapor comp
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Answer:

Explanation:

Given that:

The distillation is carried out at a pressure of 1 atm

The feed harbors 25% mole of methanol (z)

The total moles of feed is usually 100 moles

In the system, we have both methanol and water

Using the total mole balance for the distillation column.

Fz = Lx + Vy

where;

F = amount of feed

z = mole fraction of ethanol (in feed)

L = amount of liquid product out of the column

V = amount of vapor product out of the column

x = mole fraction of methanol out of the liquid

y  = mole fraction of methanol out of the vapor.

SO;

(a)

If all the feed is vaporized, then the vapor will likely have the same composition as the feed.

(b)

If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.

(c)

If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.

The balance equation would be:

Fz = (\dfrac{2}{3}F) x + (\dfrac{1}{3}F)y \\ \\ z = \dfrac{2}{3}x+\dfrac{1}{3}y

Replacing z = 0.25; we have:

0.25 = \dfrac{2}{3}x+\dfrac{1}{3}y

0.75 = 2x + y

(d)

If 2/3 of the feed is vaporized;

Then:

Fz = (\dfrac{1}{3}F) x + (\dfrac{2}{3}F)y \\ \\ z = \dfrac{1}{3}x+\dfrac{2}{3}y

replacing z = 0.25

0.25 = \dfrac{1}{3}x+\dfrac{2}{3}y

0.75 = x + 2y

6 0
3 years ago
Extra Stoichiometry Practice
Irina-Kira [14]

Answer: 50. 4g

Explanation:

First calculate number of moles of aluminium in 38.8g

Moles = 38.8g/ 26.982mol/g

= 1.44mol

By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.

4 = 2

1.4 = x

Find the value of x

x= (1.4×2)/4= 0.72 mol

0.72 moles of aluminium oxide are produced from 38.8g of aluminium

Now find the mass of aluminium produced.

Mass = moles × molar mass

= 0.72mol × 69.93 mol/g

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8 0
3 years ago
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