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lys-0071 [83]
4 years ago
13

PLEASE HELP ASAP VERY URGENT DUE TOMRROW NEED HELP I WILL MARK THE BRAINLEST

Mathematics
1 answer:
larisa86 [58]4 years ago
6 0

For the scatter plot on homework:

a) The relationship is that the test score will increase, if the time spent on homework increases

b) The function is y=8x+40, and what we need to see is what the score will be if someone puts in 3 hours of homework, x=3 in this because it means the time spent on homework:

y=8(3)+40

y=24+40

y=64

c) The score would be 40% if no time was spent doing homework

For the scatter plot on the rides:

a) y = -7/5x + 17.8

b) Anika worked 17.8 hours on Day 0

c) Decreased by 7/5 in a day.

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

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1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

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