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ahrayia [7]
3 years ago
13

I need help fast .. Which postulate could be used to prove the two triangles are congruent?

Mathematics
1 answer:
FrozenT [24]3 years ago
4 0

Answer:

asa

Step-by-step explanation:

there are two angles on both triangles and one side that with specific degrees and/or measurement. hope this is correct

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A = ???? 4 −2
irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]\neq \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=I\\\\\\B.A\neq I

Then, the matrix A isn't the inverse of matrix B.

2. If you have a matrix A:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant of the matrix is:

|A|=ad-bc

Then the determinant of B is:

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

a=3, b=2, c=1, d=4

|B|=3.4-2.1\\|B|=12-2=10

The determinant of A is:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

a=4, b=-2, c=-1, d=3

|A|=4.3-(-2).(-1)\\|B|=12-2=10

6 0
4 years ago
Need help with 9 and 10
uranmaximum [27]

Answer:

9. -4

10. 24

Step-by-step explanation:

48/-12=-4

27-3=24

7 0
3 years ago
Read 2 more answers
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

f(x,y,z)=10x+10y+3z

g(x,y,z)=5x^2+5y^2+3z^2=43

We have to find the extreme values of the function.

f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3

g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z

\Delta f(x,y,z)=\lambda \Delta g(x,y,z)

Therefore,

10=\lambda 10x\implies x=\frac{1}{\lambda}

10=10y\lambda\implies y=\frac{1}{\lambda}

3=6z\lambda

z=\frac{1}{2\lambda}

Substitute the values in g(x)

Then, we get

\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43

\frac{20+20+3}{4\lambda^2}=43

\frac{43}{4\lambda^2}=43

\lambda^2=\frac{43}{4\times 43}

\lambda=\pm\frac{1}{2}

When \lambda=\frac{1}{2} then,

x=2,y=2,z=1

When \lambda=-\frac{1}{2}

Then, x=-2,y=-2,z=-1

f(2,2,1)=10+10+3=23

f(-2,-2,-1)=-10-10-3=-23

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0
4 years ago
5ABCD is a quadrilateral. AO and BO are the angle bisectors of A
zysi [14]

Answer:

60°

Step-by-step explanation:

sum of interior angles of quadrilateral is 360°

∠C = 70°

∠D = 50°

∠C + ∠D = 120°

∴ ∠A + ∠B = 360° - 120° =240°

AO and BO bisect ∠A and ∠B

∠OAB + ∠OBA = 1/2 x ( ∠A + ∠B) = 120°

∠AOB = 180° - (∠OAB + ∠OBA) = 180° - 120° = 60°

8 0
4 years ago
Together dien and jane eat 2/3 a pizza in 4 seconds. how long would it take each of them to eat the whole pizza alone if jane ca
algol13

Answer:

10 secs for Jane and Dien is 15 secs

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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