The slope-intercept form is
y
=
m
x
+
b
y
=
m
x
+
b
, where
m
m
is the slope and
b
b
is the y-intercept.
The standard form for the equation of a circle is :
(x−h)^2+(y−k)^2=r2 ----------- EQ(1)
where handk are the x and y coordinates of the center of the circle and r is the radius.
The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (7,-4)and(1,-10) is :
((7+(1))/2,(-4+(-10))/2)=(4,-7)
So the point (4,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(7−(4))^2+(-4−(-7))^2=9+9=18
⇒r=√18
Subtituting h=4, k=-7 and r=√18 into EQ(1) gives :
(x-4)^2+(y+7)^2=18
Answer:
1, 3, and 4 would be correct answers
Step-by-step explanation:
1.) <u>-x - 2x - 3y - 2y + 1 + 1 = -3x -5y + 2</u>
2.) -3x + 2y + 3y + 2 = -3x + 5y + 2
3.) <u>-3x - y - y - y - y - y + 2 = -3x - 5y + 2</u>
4.) <u>-x - x - x - y - y - y - y - y + 1 + 1 = -3x - 5y + 2</u>
5.) x + x + x + y + y + y + y + y + 1 + 1 = 3x + 5y + 2
Hope this helps!
Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder= 
Considering, π= 3.14
⇒ lateral surface area of cylinder= 
⇒ lateral surface area of cylinder= 
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution= 
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
