Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
Answer:
A ∩ B = {4, 6}
Step-by-step explanation:
A die had 6 faces
S = {1, 2, 3, 4, 5, 6}
If A be the event of rolling an even number, then;
A = {2, 4, 6}
If B be the event of rolling a number greater than 3, then;
B = {4, 5, 6}
A ∩ B are the values that are common to both sets
A ∩ B = {4, 6}
Answer:
r=9⅓
Step-by-step explanation:
(10,r). (4,-3)
(x¹,y¹) (x²,y²)
gradient=<u>y²-y¹</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
<u>4</u>= <u>-</u><u>3</u><u>-</u><u>r</u>
3<u> </u><u> </u><u> </u><u> </u>4-10
multiply both sides by 3(4-10)to remove the denominators.
3(4-10<u>)</u>×<u> </u><u>4</u><u> </u>= <u>-</u><u>3</u><u>-</u><u>r</u><u> </u>×3(4-10)
3 4-10
(4-10)×4= (3-r)×3
16-40=9-3r
put the liketerms together
note* signs(- +) change when they cross the equal sign(=)
3r=4+40-16
3r=28
divide both sides by 3
r=28/3.
r=9⅓
Answer:
g(f(-1))=64
Step-by-step explanation:
