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Mars2501 [29]
3 years ago
15

How many ways are there to put 5 balls in 3 boxes if the balls are not distinguishable but the boxes are

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer: 5

Here are some ways:

  • 1 ball, 2 balls, 2 balls
  • 2 balls, 1 ball, 2 balls
  • 3 balls, 1 ball, 1 ball
  • 1 ball, 3 balls, 1 ball
  • 1 ball, 1 ball, 3 balls

Hope this helps!

Nat2105 [25]3 years ago
8 0

Answer:

10 ways

Step-by-step explanation:

Since the boxes are not distinguishable, the order doesn't matter in this case. Therefore, the answer would be 5 choose 3, which is \frac{5!}{2!3!} = \frac{5*4*3*2}{2*3*2} = 10

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<h3>How are integers ordered?</h3><h3 />

Integers are whole numbers such as 1, 15, and 55. There are no decimals and they do not come in the form of fractions.

Integers can be negative or positive. Positive integers are always higher than negative integers. For instance, 1 is more than -500,000.

If both integers are negative, the larger looking number is considered smaller. For instance, -5 is more than -55. For positive integers, this is the reverse with larger looking numbers being larger.

An example of the correct order of intergers based on this dataset (1, 52, -800, 86, 5, and -4) is:

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2 years ago
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<span>5x+10 = y

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<span>
</span><span>Your Answer(s)
</span><span>y = 1
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