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Mars2501 [29]
3 years ago
15

How many ways are there to put 5 balls in 3 boxes if the balls are not distinguishable but the boxes are

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer: 5

Here are some ways:

  • 1 ball, 2 balls, 2 balls
  • 2 balls, 1 ball, 2 balls
  • 3 balls, 1 ball, 1 ball
  • 1 ball, 3 balls, 1 ball
  • 1 ball, 1 ball, 3 balls

Hope this helps!

Nat2105 [25]3 years ago
8 0

Answer:

10 ways

Step-by-step explanation:

Since the boxes are not distinguishable, the order doesn't matter in this case. Therefore, the answer would be 5 choose 3, which is \frac{5!}{2!3!} = \frac{5*4*3*2}{2*3*2} = 10

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ollegr [7]

Answer:

5/24

Step-by-step explanation:

Start with the first part of the probelm 5/6 - 2/3

You need to find a common denominator of 6 and 3

common denominator= 6

so change 2/3 to 4/6

now you can subtract the top values

5/6-4/6

5-6=1

keep the denominator the same

= 1/6

Now divide 1/6  by 4/5

to divide you are going to multiply by the reciprocal so instead of 4/5 we are going to flip it to 5/4

1/6 x 5/4

5x1=5 and 6x4=24

= 5/24

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3 years ago
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Stels [109]
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3 years ago
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Find the slope of a line with equation 4y + x = 8.
uranmaximum [27]

Answer:

m = -1/4

Step-by-step explanation:

4y + x = 8

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2 years ago
Read 2 more answers
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