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3 years ago

What is the average of 17/15

Mathematics

2 answers:

blondinia [14]3 years ago

4 0

The average of 17 and 15 is 16 because if you add 17 and 15 together, and you divide them by 2, you get 16.

Oxana [17]3 years ago

3 0

^^^^^^^^^^^^^^^^^^^^16 is correct

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umka21 [38]

Answer:

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Step-by-step explanation:

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3 years ago

Jess observed that 60% of the people at a mall on a particular day shopped for clothes. If 2500 people at the mall did not shop

GalinKa [24]

2500 is 40% of the 100%
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3 years ago

Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, projvu u=(-8,8) , v= (

Jobisdone [24]

Answer:

none of the given options is true

Step-by-step explanation:

Given: u=(-8,8) , v= (-1,2)

To find: vectors $w_1,w_2$ such that $u=w_1+w_2$

Solution:

A vector is a quantity that has both magnitude and direction.

$proj_vu=\frac{u\cdot v}{\left | v \right |^2}(v)\\=\frac{(-8,8)\cdot (-1,2)}{(\sqrt{ (-1)^2+2^2})^2}(-1,2)\\=\frac{8+16}{5}(-1,2)\\=\frac{1}{5}(-24,48)\\=(-4.8,9.6)$

Let $w_1=(-4.8,9.6)$

So,

$w_2=u-w_1\\=(-8,8)-(-4.8,9.6)\\=(-8+4.8,8-9.6)\\=(-3.2,-1.6)$

So, u = $(-4.8,9.6)+(-3.2,-1.6)$

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3 years ago

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Alchen [17]

Answer: Radius = 10 cm and Arc length = 5 cm

Step-by-step explanation:

The area of a sector with radius r and central angle $\theta$ (In radian) is given by :-

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Given : A sector of a circle has area $25 cm^2$ and central angle 0.5 radians.

Let r be the radius , then we have

$25=\dfrac{1}{2}r^2(0.5)\\\\\Rightarrow\ r^2=\dfrac{2\times25}{0.5}\\\\\Rightarrow\ r^2=\dfrac{50}{0.5}=100\\\\\Rightarrow\ r=\sqrt{100}=10\ cm$

Thus, radius = 10 cm

The length of arc is given by :-

$l=r\theta=10\times0.5=5\ cm$

Hence, the length of the arc = 5 cm

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3 years ago

During its first year in business, Alice's restaurant shows a loss of $12,000. During its second year, the restaurant makes a pr

galina1969 [7]

Answer:

$10,000

Step-by-step explanation:

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3 years ago