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polet [3.4K]
3 years ago
13

Simplify the given expression.. . (7 − 3i) • (2 − i). . 4 + i. . 14 + 3i. . 11 − 13i. . 14 − 10i

Mathematics
2 answers:
Mila [183]3 years ago
3 0
The correct answer for this question is 11 - 13i.
This is how to answer this one:

(7 - 3i) (2 - i)
= [ (7*2) - (3i*2) - (7*i) + (3i*i) ]
Get the product of each term
= (14 -6i - 7i + 3i^2)

Group similar terms
= 14 - 13i - 3

Simplify.
= 11 - 13i

Side solution:
i = square root (-1)
i^2 = -1
sveticcg [70]3 years ago
3 0

Answer:

11 − 13i

(just took the quiz)


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If ABCDE is reflected over the x-axis and then translated 3 units left, what are the
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Helpeoepeoeoeo show work
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<em>IMPORTANT THIGNS TO REMEMBER:</em>

  • Has 20 lb. dog food!
  • Gives dog 1 3/5 everyday!
  • Find how much eaten after 2 days!
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<em>ANSWER:</em>

Dog has eaten 3 1/5 after 2 days!

There is 16 4/5 left in bag!

<em>EXPLANATION:</em>

Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5

Which would give you 3 1/5

So, the dog has eaten 3 1/5 lb. of dog food in 2 days.

However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.

Meaning there is 16 4/5 lb. left in the bag of dog food!

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The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

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