Answer:
i have written and above.
 
        
             
        
        
        
<span>Multiply one of the equations so that both equations share a common complementary coefficient.
       In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
   You can multiply the 1st equation by -2/5 to allow cancelling the a term.
   You can multiply the 1st equation by 5/3 to allow cancelling the b term.
   You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
   You can even multiply both equations. 
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
   3*(2a - 5b = -16) = 6a - 15b = -48
       Then add the equations
25a + 15b = -45
   6a - 15b = -48
   =
   31a = -93
   a = -3
       And then plug in the discovered value of a into one of the original equations and solve for b.</span>
        
             
        
        
        
5 to be honest I just guess
        
             
        
        
        
Answer:
Naruto
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
z = 10
Step-by-step explanation:
the steps have been attached above