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2 years ago

What opposite operation would you use to solve the equation and why? 3x = 24

Mathematics

1 answer:

mote1985 [20]2 years ago

7 0

Answer:

24 ÷ 3 = 8

x = 8

Use division.

Step-by-step explanation:

3 times a number = 24

24 divided by 3 equals that same number

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x equals negative 8 and negative 4

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How do you solve k/2+9=30

Mrrafil [7]

If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:

k / 2 + 9 = 30
k / 2 = 30 - 9
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What is the derivative of w=(t^2+1)^100 How is it 200t(t^2+1)^99?

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(t^2+1)^100

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Outside first (using power rule)

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3 years ago

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£70 is divided between Natasha, Richard & Stephen so that Natasha gets twice as much as Richard, and Richard gets three time

Korvikt [17]

The share of Natasha is £ 42

Solution:

£70 is divided between Natasha, Richard & Stephen

Total amount = 70

Let the share of natasha be "x"

Let the share of richard be "y"

Let the share of stephen be "z"

Natasha gets twice as much as Richard

x = 2y ------ eqn 1

Richard gets three times as much as Stephen

y = 3z

$z = \frac{y}{3}$ ----- eqn 2

Total amount = 70

share of natasha + share of richard + share of stephen = 70

x + y + z = 70

Substitute eqn 1 and eqn 2

$2y + y + \frac{y}{3} = 70\\\\\frac{6y+3y+y}{3} = 70\\\\10y = 210\\\\y = 21$

Substitute y = 21 in eqn 1

x = 2y = 2(21) = 42

x = 42

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3 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

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