All categories

2 years ago

Draw lines to connect each repeating decimal on the left with an equivalent fraction on the right ..

Mathematics

1 answer:

Vsevolod [243]2 years ago

6 0

The fraction and equivalent decimals are 348/990 = 0.3515151 ,316/900 = 0.3511111 , 351/999 = 0.351351351 ,16/90 = 0.1777 and 17/99 = 0.171717.

<h3>What is the arithmetic operator?</h3>

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

If we divide the fraction given in the table then the corresponding decimal obtained are ;

348/990 = 0.3515151

316/900 = 0.3511111

351/999 = 0.351351351

16/90 = 0.1777

17/99 = 0.171717

Hence "The fraction and equivalent decimals are 348/990 = 0.3515151 ,316/900 = 0.3511111 , 351/999 = 0.351351351 ,16/90 = 0.1777 and 17/99 = 0.171717".

To learn more about the arithmetic operators,

brainly.com/question/25834626

#SPJ2

You might be interested in

I need help thank you

Alenkasestr [34]

Hello again!
So just like in the last problem you would do the same here.
Solve for 3y + 6 = 3
Subtract 6 from both sides.
3y = -3
Divide by 3.
y = -1
Now plug it into 8y + 2.
8(-1) + 2 = ?
-8 + 2 = ?
= -6
I hope this helps love! :)

5 0

3 years ago

1000 grams decreased by 94%

gregori [183]

$subtract\ 94\%\ of\ 1000\ from\ 1000\\\\1000-94\%*10000=1000-0.94*1000=1000-940=60\\\\
1000\ grams\ decreased\ by\ 94\%\ is\ 60.$

3 0

3 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

3 years ago

Read 2 more answers

HELP PLEASE!!! URGENT!!!

Hatshy [7]

F(x) = 3x + 7.....g(x) = 4x - 2

A. (f + g)(x)
3x + 7 + 4x - 2
7x + 5 <====

B. (f * g)(x)
(3x + 7)(4x - 2) =
3x(4x - 2) + 7(4x - 2) =
12x^2 - 6x + 28x - 14
12x^2 + 22x - 14 <===

C. f[g(x)]
3(4x - 2) + 7 =
12x - 6 + 7 =
12x + 1 <===

3 0

3 years ago

3. Solve for y: -5x + 2y = 14

Schach [20]

Answer:

y= -1

Explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

8 0

3 years ago

Read 2 more answers