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Marizza181 [45]
3 years ago
8

How are the particles in this model different from real gas particles

Chemistry
1 answer:
ddd [48]3 years ago
3 0
In a model, the particles are not the actual size. They are just representing the gas particles. In a gas, the particles are smaller and in their own material 
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D water expands when it freezes

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3 years ago
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2. Why is the lonic compound Nacl (table salt) able to dissolve in a glass of the molecular compound water (H20)? (3 points)
melomori [17]

Answer:

The correct answer is C ions from the solute molecules have a strong attraction to the polar solvent molecules.

Explanation:

NaCl or Sodium chloride is an ionic compound which easily get dissolved in polar molecular compound such as water(H2O).

      Both NaCl and H2O are polar compound because the atoms that forms NaCl and H2O have vast difference in their electronegativities.As a result the bonding electrons in both NaCl and H2O are not equally shared.

     NaCl get dissolved in water molecules by dipole dipole interaction.  

6 0
3 years ago
Can somebody plz tell me which one I should circle for each question thanks!!!
marusya05 [52]

Answer:

1. False

2. True  

3. True

4. True

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Explanation:

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2 years ago
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A quantity of 0.225 g of a metal M (molar mass = 27.0 g/mol) liberated 0.303 L of molecular hydrogen (measured at 17°C and 741 m
Lana71 [14]

Answer:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3

Explanation:

0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

Pressure of the gas ,P= 741 mmHg= 0.9633 atm

Volume occupied by gas , V = 0.303 L

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol

Moles of hydrogen gas produced = 0.01225 mol

2M+2xHCl\rightarrow 2MCl_x+xH_2

Moles of metal =\frac{0.225 g}{27.0 g/mol}=8.3333 mol

So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

\frac{8.3333}{0.01225 mol}=\frac{2}{x}

x = 2.9 ≈ 3

2M+6HCl\rightarrow 2MCl_3+3H_2

MCl_3\rightarrow M^{3+}+Cl^-

Formulas for the oxide and sulfate of M will be:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3.

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3 years ago
A high jumper jumps 2.09m. If the jumper has a mass of 72kg, what is his gravitational potential energy at the highest point of
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