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Soloha48 [4]
3 years ago
11

What is cloud ? How does it affect on weather ?​

Chemistry
2 answers:
Lapatulllka [165]3 years ago
7 0

Clouds are xondense form of water vapour over dust particles present in the upper atmosphere.

It effects the weather as when the clouds get heavy they get precipitate in the form pf rain, snow, hail. because of these factors temperature goes down and make us feel cold.

HOPE THIS WILL HELP U

Korolek [52]3 years ago
3 0

You already asked this on the prior question but I will go more in depth here.

Alright so clouds are condensed masses of water vapor that float around the different levels of the atmosphere. The warmer the air, the higher the clouds tend to be. However lets say in the case of a tornado you have the hot air coming in from the south and then the cold air hitting the warm air and as it collides it forms rotation causing it to spin downward at incredible speeds. However there are multiple other factors for producing storms like that.

Another thing that I would add to it is that clouds come in all different shapes and sizes.

<u>-Cirrus</u>

<u>-Cirrostratus</u>

<u>-Cirrocumulus</u>

<u>-Altocumulus</u>

<u>-Altostratus</u>

<u>-Nimbostratus</u>

<u>-Cumulus</u>

<u>-Stratus</u>

<u>-Cumulonimbus</u>

<u>-Stratocumulus</u>

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3 years ago
How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2
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How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

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Hitrogen (N) has an atomic number of 7 and an atomic mass of 14. Which of the following correctly shows the electron
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3 years ago
Given the following: I) N20(g) 1/2 02(g) 2 NO(g) II) N2(g) 02(g) 2 NO(g) Ke= 4.1 x 10-31 Ke= 1.7 x 10-13 Find the value of the e
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To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:

2NO-------->N_2O+1/2O_2 : (reaction 1' :K'_1 =1/K_1=2.4x10^ 3^0)

N_2+O_2-------->2NO: (reaction 2 :K_2 =1.7x10^-^1^3)

____________________________

N_2+1/2O_2-------->N_2O: (reaction 3)

Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30

Finally, the new equilibrium constant K3 is the product of the previous constants:  

K3=K1'*K2=4.2x10^17

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