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eduard
3 years ago
8

Calculate the kinetic energy of a 150 g baseball moving at a speed of 40. m/s (89 mph).

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
6 0
Kinetic Energy= 0.5 times velocity squared times mass
So KE= 0.5times 150 times 40 squared

(Use a calculator)
And don't forget units
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Given the equilibrium constants for the following two reactions at a 298K:NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40NiO(s) +CO(g) ⇌ N
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Answer:

The value  is  K_C =  \frac{40}{600}

Explanation:

From the question

   The equation given is  

            NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40          (1)

            NiO(s) +CO(g) ⇌ Ni(s) +CO2(g) Kc=600         (2)

Generally the reverse of the second equation as shown below

            Ni(s) +CO2(g) ⇌  NiO(s) + CO(g)                 (3)

The equilibrium constant becomes    K_c  ' =  \frac{1}{600}  

 Now  adding  1  and  3 we obtain

      NiO(s) + H2(g)+ Ni(s) +CO2(g) ⇌ Ni(s) + H2O(g)+NiO(s) + CO(g)        

               CO2(g) + H2(g) ⇌ CO(g) + H2O(g)

Hence the equilibrium constant for the resulting equation is mathematically evaluated as

           K_C =  K_c' *  K_c

=>       K_C =  \frac{1}{600}  *  40

=>         K_C =  \frac{40}{600}

       

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