Answer:
These tests determine the solubility of the compounds formed upon adding the test solution
Explanation:
Addition of Ba(NO₃)₂ will cause a precipitate ((Ba)₂SO₄) to form in the solution of (NH₄)₂SO₄. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is ammonium sulfate can be determined.
Addition of NaCl solution will cause a precipitate (AgCl) to form in the solution of AgNO₃. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is silver nitrate can be determined.
If no precipitates form, then the unknown solution must be KCl.
Which of the following statements does not describe the structure of an atom?
A) The electron cloud is a small and compacted space around the nucleus.
Answer:
250L
Explanation:
Data;
V1 = 200L
P1 = 10atm
T1 = 400K
T2 = 100K
P2 = 2atm
V2 = ?
To solve this question, we'll have to use the combined gas equation which is a combination of Boyle's law, Charles law and pressure law.
From combined gas equation,
(P1 × V1) / T1 = (P2 × V2) / T2
P1 × V1 × T2 = P2 × V2 × T1
Solve for V2,
V2 = (P1 × V1 × T2) / P2 × T1
V2 = (10 × 200 × 100) / (2 × 400)
V2 = 200,000 / 800
V2 = 250L
The final volume of the gas is 250L
A intense property of substance is a physical quantity.
Answer:
Q = -150.8 J
Explanation:
Given data:
Mass of copper = 10.0 g
Initial temperature = 80.0°C
Heat released = ?
Final temperature = 40.0 °C
Specific heat capacity of copper = 0.377J/(g·ºC)
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40.0 °C - 80.0 °C
ΔT = -40.0 °C
by putting values,
Q = 10.0 g × 0.377J/g·ºC× -40.0 °C
Q = -150.8 J