Answer:
I would say b hope this helps
Explanation:
have a good day btw i had this question before:D
Answer:
History of composition
Years Material Weight (grains)
1944–1946 gilding metal (95% copper, 5% zinc) 48 grains
1947–1962 bronze (95% copper, 5% tin and zinc) 48 grains
1962 – September 1982 gilding metal (95% copper, 5% zinc) 48 grains
October 1982 – present copper-plated zinc (97.5% zinc, 2.5% copper) 38.6 grains
Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
The number of years required for 1/4 cobalt-60 to remain after decay is calculated as follows
after one half life 1/2 of the original mass isotope remains
after another half life 1/4 mass of original mass remains
therefore if one half life is 5.3 years then the years required
= 2 x 5.3years = 10.6 years
The answer is D, because "Animals without a backbone are invertebrates."
