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Komok [63]
3 years ago
7

How many moles are in 213 grams of NaCl?

Chemistry
1 answer:
Nata [24]3 years ago
5 0

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

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consider the following equilibrium:h2co3(aq) h2o(l) h3o (aq) hco3-1(aq).what is the correct equilibrium expression?
MAVERICK [17]

The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:<span>

<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

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4 0
3 years ago
Select all the correct answers.
pochemuha

<u>Out of all given option, the following statements are true about a system:</u>

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Answer: Option A and B

<u>Explanation:</u>

A system is "a complicated item whose parts or segments are identified with probably a portion of different segments", it very well may be material or calculated. All systems have piece, structure, and condition, yet just material systems have instruments (or forms), and just some material systems have shape.

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8 0
2 years ago
The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 x 10-15 s-1 at 298 K and a rate constant of 8
laiz [17]

Answer:

The correct answer is 160.37 KJ/mol.

Explanation:

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19.29 = Ea/R * 0.001

Ea = 160.37 KJ/mol

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3 years ago
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