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Maurinko [17]
3 years ago
11

Which one is denser? question 2 options: the earth (a solid object) the sun, which is about 300,000 times more massive than the

earth mars jupiter?
Chemistry
1 answer:
tankabanditka [31]3 years ago
6 0
The Earth, Mars or Jupiter should be denser than the Sun. Density is defined by mass and volume — components of object or matter. Although the sun is huge, it’s component is made up of mostly gas (hydrogen and helium). While Earth, though smaller than the Sun, contains heavier elements such as iron, sulfur, rocks, sediments, granite, basalt and water. Mars (composed of rocks and nutrients) and Jupiter (contains gases and compounds) as well are denser when compared to the Sun’s density. Referencing to our basic understanding of matter: solid and liquid should be heavier than gas.
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A 76.00-pound flask of mercury costs $151.50. The density of mercury is 13.534 g/cm3.
Agata [3.3K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Please see below solution:

1 lb Hg x (151.50/76 lb) = cost of 1 lb. 
<span>cost 1 lb x (1g/453.6 g) = cost of 1 g.</span>
8 0
3 years ago
Read 2 more answers
Use Hess's Law to calculate the enthalpy change for the reaction
Marysya12 [62]

Answer:

ΔH = 125.94kJ

Explanation:

It is possible to make algebraic sum of reactions to obtain ΔH of reactions (Hess's law). In the problem:

1. 2W(s) + 3O2(g) → 2WO3(s) ΔH = -1685.4 kJ

2. 2H2(g) + O2(g) → 2H2O(g) ΔH = -477.84 kJ

-1/2 (1):

WO3(s) → W(s) + 3/2O2(g) ΔH = 842.7kJ

3/2 (2):

3H2(g) + 3/2O2(g) → 3H2O(g) ΔH = -716.76kJ

The sum of  last both reactions:

WO3(s) + 3H2(g) → W(s) + 3H2O(g)

ΔH = 842.7kJ -716.76kJ

<h3>ΔH = 125.94kJ </h3>
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3 years ago
Spring day characterized by day and night of equal lengths
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<span>Day and night are not exactly of equal length at the time of the March and September equinoxes. The dates on which day and night are each 12 hours occur a few days before and after the equinoxes.</span>
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Aleksandr [31]

messed up oops !!!!!!!!!


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CaHeK987 [17]

Heat the sulfuric acid solution and adding copper carbonate in it.

<h3>Improvement require in this experiment</h3>

The method could be improved by heating sulfuric acid solution and add copper carbonate into the solution of sulfuric acid. Add the copper carbonate until it is present in excess amount. After that filter the extra amount of copper carbonate so in this way the blue copper sulfate crystals are produced.

Learn more about copper here: brainly.com/question/3157958

5 0
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