Answer:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Explanation:
When a forest burns and all that's left is some ash, most of the mass of the trees go to the atmosphere, in the form of carbon dioxide.
In a total combustion process of organic matter,<em> the two molecules produced are carbon dioxide and water. </em>(CO₂ and H₂O)
The equation for the combustion of glucose is:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
<span>When BaCrO4 dissolves, it dissociates like this: BaCrO4 (s) --> Ba2+ + CrO42-
</span>
<span>The expression for Ksp is [Ba2+] x [CrO42-]
</span>
There is a 1:1 molar ratio between the BaCrO4 that dissolves and Ba2+ and CrO42-
that are in solution. This means that, when 1.08×10⁻⁵ moles per liter of BaCrO4 dissolves, it produces 1.08×10⁻⁵ mol/L of Ba2+ and 1.08×10⁻⁵ of <span>CrO42-. So, applying the expression:
</span>
Ksp = (1.08×10⁻⁵ ) x (1.08×10⁻⁵ )
= 1.166 x 10⁻¹⁰
<span>This question is simple, answers are D and C respectively</span>
Answer:
Answer is shown on the paper :D
Explanation:
Remember to follow sig-figs.
