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Nataly_w [17]
2 years ago
5

How many atoms of magnesium metal are needed to produce 3.87 moles of magnesium oxide

Chemistry
2 answers:
Ket [755]2 years ago
4 0

Answer:

48.42g of Mg

Explanation:

nata0808 [166]2 years ago
3 0

Answer:

they other guys is ri gh gt

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Which two types of cells are involved in fertilization?

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  • During fertilisation, the gametes (an egg and sperm) fuse to form a zygote.

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2 years ago
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3 years ago
Can someone please help me here is the question i will give u extra points All of the following can be inherited traits except f
kirill115 [55]

Answer:

dialect.

Explanation:

if you look at parents and their children. you see their eyes and you see the child's eyes. they could have the same eyes. if you look at both noses you can see that one is similar to the other one. hair texture, lets say a mom has thin hair, and the father also has thin hair. the child more likely will have thin hair as well. you only inhertit dialect when your around that person for a long time.

5 0
2 years ago
Read 2 more answers
ANSWER QUICK I VOTE AS BRAINLIEST
77julia77 [94]
The relative humidity of the air is the ratio of the actual amount of moisture in the air to the fully saturated amount. There for the answer is 33.1% or 3.3g/kg
5 0
2 years ago
The flame produced by the burner of a gas (propane) grill is a pale blue color when enough air mixes with the propane (C3H8) to
adelina 88 [10]

Answer:

At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane

Explanation:

The combustion stoichiometry is as follows:

      C₃H₈ + 5O₂  = 4 H₂O + 3CO₂      The molecular weights (g/mol) are:

MW  44    5x32      4x18    3x44

So each gram of propane is 1/44 = 0.02272 mol propane

and will need 5 x 0.02272 = 0.1136 mol oxygen

At 0.21 mol fraction oxygen in air, 0.1136 / 0.21 = 0.54 mol air is needed to burn the propane.

At the low pressure in the burner we can use the Ideal Gas Law

PV=nRT, or V = nRT/P

P = 1.1 x 101325 Pa = 111457 Pa

T = 195°C + 273 = 468 K

R = 8.314

and we calculated n = number of moles air = 0.54 mol

So V m³ = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 litres air.

6 0
3 years ago
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