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3 years ago

Chad bought 7 pounds of strawberries for $10.80. What was the cost, c, of 1 pound of strawberries?

Mathematics

2 answers:

never [62]3 years ago

6 0

If you divide the price (10.80) by the weight (7lbs) you would get 1.54 per lbs

dangina [55]3 years ago

4 0

Do 10.80 ÷ 7 and that will be your answer.

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The model of a shopping mall is made using a scale of 1: 50

jekas [21]

Answer:

20 m

Step-by-step explanation:

Given that :

Scale of 1 : 50 is used to make a model

If the model has a height of 40 cm ; the height of the house is:

Then, the actual height of the house is (40 * 50) = 2000 cm

Thus the height of the house in metre is :

100cm = 1 meter

2000 cm = 2000 / 100

2000 cm = 20 meter

Height of house in meter = 20 meter

3 0

3 years ago

In parallelogram ABCD, the measure of angle ABC is 130, find the measure, in degrees of angle DAB

77julia77 [94]

Angle ABC = 130
Angle ABC = Angle ADC = 130 (Opposite angles are equal)
Angle DAB = 180 - 130 = 50 (consecutive interior angles)

I HOPE IT IS HELPFUL:D

6 0

3 years ago

Read 2 more answers

Rewrite in radical form (-243)2/5

nadezda [96]

Answer:

243 and 2 over 5

Multiply

(−243) and 2 over 5 . −486 over 5.

Move the negative in front of the fraction.

−486 over 5

Exact Form:

-486 over 5

Decimal Form:

-97.2

Mixed Number Form:

-97 and 1 over 5

7 0

3 years ago

Susan made the following 3-dimensional figure from a net. What 2-dimensional shapes are used to make the faces of the figure?

konstantin123 [22]

Answer:

Step-by-step explanation:

I don't know if there was a picture, but d will made a triangular prism. All are possible but they will look more like a dome.

5 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago