The value of
is 2500, when
and
.
Given that,
and
.
We need to find the value of
.
<h3>What is an
arithmetic sequence?</h3>
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
Now, to find the value of
:




Therefore, the value of
is 2500.
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Answer:
a=2
b=3
c=5
d=-3
Step-by-step explanation:
a + b = c
a-c=d
a+b=5
a+b =5
a = 2
2+b =5
Subtract 2 from each side
2+b-2 =5-2
b=3
a + b = c
2+3 = c
5=c
a-c=d
2-5 =d
-3 =d
The distance are
a. 42.42
b. 15. 52
<h3>How to solve for the distance</h3>
80 = 65 + <ABC
<ABC = 80 - 65
= 15
Through the use of sine rule we would have
By using sine rule,
Sine 15/a = sine 135/b =
sin 30/30.
Next we have to solve b by cross multiplying
b = (30× sin135) / sin 30
= 21.21/0.5
b = 42.42 km
Also, the value of a will be:
= (42.42 × sin 15) / sin 135
= 10.98/0.7071
= 15.52
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Answer:
b.
( -3, -5)
Step-by-step explanation:
6x + 13 = 2x + 1
6x -2x = 1-13
4x = -12
x = -12/4 = -3
y = 6x + 13
y = 6(-3) +13 = -18+13 = -5
(x, y) = (-3,-5)