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liberstina [14]
3 years ago
7

Use the slope formula to determine the equation of the line (2,.75) and (4,.25)

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

y=-0.25x+1.25

Step-by-step explanation:

hope this helps u

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Can some one help me please
kykrilka [37]

Answer:

The Domain is X, range is Y

Step-by-step explanation:

Domain and Range is just another term for X-axis and Y-axis

3 0
3 years ago
Round the following number to the indicated place. 66.1086 to hundredths
nikdorinn [45]

Answer:

66.11

Step-by-step explanation:

We are given that  a number

66.1086

We have to round the number to hundredths

Place of 6=One;s

Place of second 6=Tens

Place of 1=Tenths

Place of 0=Hundredths

Place of 8=Thousandths

Place of 6=Ten thousandths

Thousandths place is 8 which is greater than 5 therefore, one will be added to hundredth place and other number on the left side of  hundredth place remain same and the numbers on the right side of hundredth place will be replace by zero.

Therefore, the given number round to hundredths=66.11

7 0
3 years ago
Select all triangles whose side lengths prove they are right triangles. You must select all that apply.
Bogdan [553]
It is D.

Reason. 3^2 is 9, 4^2 is 16.
16+9= 25
The square root of 25 is 5.
Therefore it is D.
6 0
2 years ago
Read 2 more answers
A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

Thus 2 \times 10^{19} times more stars are there in universe compared to human eye can see

5 0
3 years ago
What number goes in the box below to make the statement true?
Schach [20]

Answer:

5000

Step-by-step explanation:

4 0
3 years ago
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