Answer:

Step-by-step explanation:

Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
D
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y =
x + 9 ← is in slope- intercept form
with y- intercept c = 9
then the line crosses the y- axis at (0, 9 )
Y=-2x+0 haahahaha hope i helped i think
Answer:
2.7 The second question I am unsure of because side EF is clearly labeled 7, if they meant to ask for the value of x in the second question then your answer is 12
Step-by-step explanation: