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3 years ago

What is the next 2 numbers in the sequence? 343,131413,11131114113

Mathematics

1 answer:

VashaNatasha [74]3 years ago

5 0

Answer:

111113111114111113 and 111111131111111411111113

Step-by-step explanation:

Here we want to know the next two numbers in the sequence.

The key here is that we shall be placing the same number of digit 1 between each of the digits 3 4 3

We went from a single 1 to triple, so the next will be 5 digit 1 and the next will be 7 digit 1

So the next number after the third will be;

111113111114111113

The next number after this will be;

111111131111111411111113

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3 years ago

A rocket leaves the surface of Earth at time t=0 and travels straight up from the surface. The height, in feet, of the rocket ab

erastovalidia [21]

Answer:

Remember that:

Speed = distance/time.

Then we can calculate the average speed in any segment,

Let's make a model where the average speed at t = t0 can be calculated as:

AS(t0) = (y(b) - y(a))/(b - a)

Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.

Then:

if t0 = 100s

AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s

if t0 = 200s

AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s

if t0 = 300s

AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s

if t0 = 400s

AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s

So for the given options, t = 400s is the one where the velocity seems to be the biggest.

And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.

Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.

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3 years ago

Calculate the length of the third side of this triangle. 6 cm, 8 cm

stiv31 [10]

<h2>By pythagoras theoram </h2>

 $c = \sqrt{a2 + b2}$ 

6²-- 8²

18--16

2 

Hence the third value 2 

Step-by-step explanation:

I think this is a helpful for you 

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3 years ago

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lisov135 [29]

Answer:

no it's not

hope it helps;)

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4 years ago

Read 2 more answers