Answer: Temperature of one liter of phosphine gas with a mass of 1.725 g and gas pressure of 0.9910 atm is 
Explanation:
According to the ideal gas equation:
PV=nRT
P = Pressure of the gas = 0.9910 atm
V= Volume of the gas= 1.0 L
T= Temperature of the gas in kelvin = ?
R= Gas constant =
n= moles of gas= 


Thus the temperature (in °C) of one liter of phosphine gas with a mass of 1.725 g and gas pressure of 0.9910 atm is 
Answer:
0.047 M
Explanation:
Given data:
Volume of KF = 93.2 mL
Molarity of KF = 2.03 M
volume of water added= 3.92 L
Solution:
First of all we will calculate the number of moles of KF.
number of moles = Molarity × volume in litter
number of moles = 2.03 mol/L × 0.0932 L
number of moles = 0.189 mol
Molarity of solution:
Total volume = 3.92 L + 0.0932 L = 4.0132 L
Molarity = number of moles / volume in litter
Molarity = 0.189 mol/ 4.0132 L
Molarity = 0.047 M
B is the correct answer if I remember
Answer:
dependent variable: plant growth
independent: sunlight impact/amount of light
Explanation: