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Sunny_sXe [5.5K]
2 years ago
12

Draw the Lewis structure for the polyatomic formate anion. Be sure to include all resonance structures that satisfy the octet ru

le.
Chemistry
1 answer:
givi [52]2 years ago
8 0

Answer:

Lewis structure of polyatomic formate anion.

Explanation:

To draw Lewis structure for any chemical species,

1)Count the total number of valence electrons present in it.

This can be obtained by adding valence electrons of each constituent atom.

2)Arrange those valence electrons in such a way that each atom should attain eight electrons around it to satisfy octet theory.

The structure of formate ion and its Lewis structure are shown below:

HCOO- is the formate ion.

It has total:

1+4+6+6+1 = 18 valence electrons.

Since, hydrogen has one, carbon has four and oxygen has six valence electrons and the charge of the anion is one.

Arrange this 18 electrons in such a way that each atom should get 8 electrons around it.

Resonance structures of formate ion:

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<u>Answer:</u> The force that must be applied is 15 N.

<u>Explanation:</u>

Force exerted on the object is defined as the product of mass of the object and the acceleration of the object.

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F = force exerted = ?

m = mass of the object = 3 kg

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Putting values in above equation, we get:

F=3kg\times 5m/s^2=15N

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How much faster does ethane (C2H6) gas travel compared to chlorine gas?
zimovet [89]

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

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M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

5 0
3 years ago
A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10
Alex17521 [72]

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8O_{2}  ⇒P_{4} O_{6} +P_{4} O_{10}

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=\frac{117.9}{31} =3.80

Moles of O_{2} =\frac{117.9}{31} =3.80

No. of moles of formed product are equal and is \frac{1}{8}th of mole of any of reactant.

Thus weight of  P_{4} O_{6} =\frac{3.80}{8}×220 ≈103.41

        weight of  P_{4} O_{10} =\frac{3.80}{8}×284 ≈133.48

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3 years ago
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