Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15
From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,
0.048 is the probability that more than 950 message arrive in one minute.
(5x^3-7)(2x^2+1 answerrrrrrrrrr
The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have: L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides: P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2)) P = 8 * (π ^ (1/2))
Answer:
C=0.55M+24.65
Step-by-step explanation:
0.40M+0.15M=0.55M
18.95+5.70=24.65
Answer: A: 3x^2y^(3/2)
Step-by-step explanation:
This can be written as
(81*x^8*y^6)^(1/4)
Then multiply each exponent by (1/4):
81^(1/4)*x^(8(1/4))y^6(1/4))
81^(1/4) = 3
x^(8(1/4)) = x^2
y^6(1/4)) = y^(3/2)
The result: 3x^2y^(3/2)
