if the equatorial diameter of the sun is 1.39 milion kilometers, how many kilometers is the sun's radius

How does the resistance change as you add bulbs to a series circuit? The resistance does not change. The resistance decreases. T

Anon25 [30]

Light bulbs are loads, so they have a certain amount of resistance associated with them. In series, Resistance total = R1 +R2 +R3...
So the more resistance you add, the more resistance there is! Therefore, the resistance increases!

6 0

4 years ago

Read 2 more answers

1. A record with a radius of 0.3m spins in a clockwise circle with a centripetal

Hitman42 [59]

Solve for the linear/tangential speed:

a = v²/r

where a = centripetal acceleration, v = speed, and r = radius.

4.7 m/s² = v²/(0.3 m)

v² = (0.3 m) (4.7 m/s²)

v ≈ 3.96 m/s

For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2π (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is

(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s

Take the reciprocal of this to get the period:

1 / (7.46 rev/s) ≈ 0.134 s/rev

So it takes the record about 0.134 seconds to complete one revolution.

6 0

3 years ago

A certain electric circuit obeys Ohm's law. If the resistance of the circuit is doubled, what will happen to the current through

netineya [11]

Answer:

currrent will be halved

Explanation:

v = ir

v/r = i multiply both sides by 1/ 2

v / (2r) = 1/2 i

4 0

3 years ago

If the detector readings are proportional to the amplitude of the microwave E field, the data from the first polarization experi

ololo11 [35]

Answer:

Fields and variables are proportional

Explanation:

To solve the problem we must first identify the Vector Intensity,

The intensity is given by:

$I = I_ {0} cos^2 (\theta)$

We also know that the change given by the Intensity is always the square of the amplitude,

This is,

$I = A ^ 2$

The intensity is proportional to the change exerted on $cos ^ 2 (\theta)$

That is to say that in turn the amplitus is proportional to the Intensity.

On the other hand, relating the two variables we have

$A ^ 2 = A ^ 2_ {0} cos ^ 2 \theta$

$A = A_ {0} cos \theta$

In this way we can conclude that the electric field of intensity is also proportional to $cos ^ 2 \theta$

7 0

3 years ago

A moving hammer hits a nail and drives it into a wall. if the hammer hits the nail with twice the speed, how much deeper will th

vlabodo [156]

This is an example of work-energy theorem where it lets a person accumulate the strength of the muscles over the duration of the swing, allowing much bigger forces as the hammer hits the nail.
Moreover, the work done on an object by a net force is equals to the change in kinetic energy of the object, which is expressed as W = KEf - KEi. 
Therefore, if the hammer hits the nail with twice the speed, it corresponds to 4 times the energy and four times the driving distance. If the hammer hits with three times the speed, the driving distance is 9 times as much.

5 0

3 years ago