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boyakko [2]
3 years ago
10

An empty parallel plate capacitor is connected between the terminals of a 16.7-v battery and charges up. the capacitor is then d

isconnected from the battery, and the spacing between the capacitor plates is doubled. as a result of this change, what is the new voltage between the plates of the capacitor?
Physics
1 answer:
katen-ka-za [31]3 years ago
4 0
16.7V * 2 = 33.4V
_____
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Answer:

θ = 29.38°

Explanation:

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Now, the vertical component of the normal force is; F_n(cos θ)

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μ_s = (tan θ)

Thus, θ = tan^(-1) μ_s

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θ = tan^(-1) 0.563

θ = 29.38°

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