So basically first try to find the co2 then convert it
Fe + 3NaBr → FeBr3 + 3Na
The Na is replaced by the Fe atom.
Answer:
Protons and Neutrons
Explanation:
Neutrons and protons constitute almost all of an atom's mass. The third type of stable particle is the electron. Electrons have a negative charge but are extremely small and have a mass only 1/1850 that of a proton or neutron. They are so small that for practical purposes they do not contribute to the mass of the atom.
I hope this helped!
First step is to calculate the mass of Ag in each compound separately:
From the periodic table:
molar mass of Ag is 107.87 gm
molar mass of Cl is 35.45 gm
molar mass of Br is 79.9 gm
For AgCl, mass % of Ag = [107.87/143.32] x 100 = 75.26%
For AgBr, mass % of Ag = [107.87/187.77] x 100 = 57.45 %
Second step is to calculate the mass % of each compound in the mixture:
Assume mass % of AgCl is y and that of AgBr is (1-y) as the total percentage is 100% or 1
0.6094 = 0.7526 y + 0.5745 (1-y)
y = 0.8716
This means that the mixture is almost 87% AgCl and 13% AgBr
The mass % of chlorine and bromine together is (100%-60.94%) which is 39.06%
mass % of chlorine = (1-0.6094)(0.8716) x 100 = 34.044%
mass % of bromine = 39.04 - 34.044 = 5.056%
Answer:
298 kPa
Explanation:
Data Given:
initial Volume of oxygen V1= 48.0 L
Final Volume of oxygen V2= 16.0 L
initial pressure of oxygen P1= 99.3 kPa
initial Pressure of oxygen P2= ?
Solution:
The Boyle's law formula will be applicable here at constant temperature
Boyle's law formula
P1V1 = P2V2
As we have to find final pressure so rearrange the equation
P2 = P1V1 /V2 ....................(1)
Put values in Equation 1
P2 = 99.3 kPa x 48 L /16 L
P2 = 298 kPa
So the final pressure will be 298 kPa