I haven't done these in some time, so I'm not sure if they are 100% right.
1) 6.3 moles of H2( 2 mol of NH3 / 3 mol of H2)= 4.2 mol of NH3
6.3 moles of H2( 2 mol of NH3/ 3 mol of H2)(17.04 g of NH3/1 mol NH3)= 71.57 g of NH3
2) 2.5 moles of N2(2 mol of NH3/1 mol of N2)= 5 moles of NH3
2.25 moles of N2(2 mol of NH3/ 1 mol of N2)(6.02x10^23 particles/ 1 mol of NH3)= 3.01x10^24 particles of NH3
3) 425 g of NH3(1 mol of NH3/17.04 g NH3)= 24.9 moles of NH3
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)(28.02 g of N2/1 mol N2)= 349 g of N2
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)= 12.5 mol of N2
4) 10 moles NH3(3 moles of H2/2 moles of NH3)= 15 moles H2
10 moles NH3(3 mol of H2/2 mol of NH3)(2.02 g of H2/1 mol of H2)= 30.3 g of H2
30.3 g = .0303 liters of H2
The correct answer is 0.04287 M
It is given that the rate constant of the reaction is 6.2 × 10⁻⁵ mol/L/s
Thus, as the rate of the reaction is in mol/L/s, it is a zero order reaction.
The initial concentration of a is 0.0500 M, and there is a need to find the concentration of a after 115 seconds. This can be done with the help of the equation:
[A]o -[A] = kt
[A] = [A]o - kt
= (0.0500 M) - (6.2 × 10⁻⁵) (115 s)
= 0.04287 M
Answer:
a. First order.
b. 
c. 
d. ![[A]=0.111M](https://tex.z-dn.net/?f=%5BA%5D%3D0.111M)
Explanation:
Hello.
a. In this case since the slope is in s⁻¹ we can infer that the lineal form of the rate law is:
![ln[A]=-kt+ln[A]_0](https://tex.z-dn.net/?f=ln%5BA%5D%3D-kt%2Bln%5BA%5D_0)
Which is also:
It means that the reaction is first-order as slope equals the negative of the rate constant which also has units of first-oder reaction.
b. Since the slope is −3.7 x 10−3 s−1 the rate constant is:
c. For first-order reactions, the half-life is:
d. In this case, since the integrated first-order rate law is:
![[A]=[A]_0exp(-kt)](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0exp%28-kt%29)
The concentration once 220 seconds have passed is:
![[A]=0.250Mexp(-3.7x10^{-3}s^{-1}*220s)\\\\](https://tex.z-dn.net/?f=%5BA%5D%3D0.250Mexp%28-3.7x10%5E%7B-3%7Ds%5E%7B-1%7D%2A220s%29%5C%5C%5C%5C)
Regards.
Answer:
i think the answer is D-Transpirtation
