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ololo11 [35]
3 years ago
6

A sample of 325 mg of neon occupies 2 dm^3 at 20.0 c. use the perfect gas law to determine the pressure of the gas.

Chemistry
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

0.1935atm is the pressure of the gas.

Explanation:

In the problem you have the mass of Neon (You can obtain moles using molar mass), you have volume, and temperature. You can use general ideal gas law to solve pressure:

PV = nRT

P = nRT / V

<em>Where P is pressure in atm, n are moles, R is gas constant (0.082atmL/molK), T is absolute temperature (20.0°C + 273.15 = 293.15K), and V is volume in L = Volume in dm³</em>

<em />

<em>Moles gas:</em>

Molar mass Ne = 20.1797g/mol

0.325g * (1mol / 20.1797g) = 0.0161 moles

Replacing:

P = nRT / V

P = 0.0161 moles * 0.082atmL/molK * 293.15K / 2L

P = 0.1935atm is the pressure of the gas

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Answer:

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Explanation:

In alpha decay, the element subtracts 4 from its mass number and subtracts 2 from its atomic number.

So if we end with Uranium-235, which has an atomic number of 92:

235+4 = 239

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lisov135 [29]

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What are the moles of gas are in a 30 liter scuba canister if the temperature of the canister is 300 K and the pressure is 200 a
Lady_Fox [76]

Answer:

n = 243.605

Explanation:

Given

Pressure, P = 200\ atm

Temperature, T = 300k

Volume, V = 30L

Required

Calculate the number of moles

We'll apply the following formula to solve this question

n = \frac{pV}{RT}

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The above equation is an illustration of the ideal gas law

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n = \frac{pV}{RT}

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