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DIA [1.3K]
3 years ago
5

For sulfurous acid (h2so3, a diprotic acid) write the equilibrium dissociation reactions and the corresponding expressions for t

he equilibrium constants
Chemistry
1 answer:
Ne4ueva [31]3 years ago
7 0
Since the acid is diprotic, there are two equilibrium dissociation reactions for it. Consequently, there will also be two expression for equilibrium constants, Ka₁ and Ka₂.

First reaction:
H₂SO₃ ⇄ 2H⁺ + HSO₃²⁻          ------>     Ka₁ = [H⁺][HSO₃²⁻]/[H₂SO₃]

Second reaction:
HSO₃²⁻ ⇆ H⁺ + SO₃²⁻             ------>     Ka₂ = [H⁺][SO₃²⁻]/[HSO₃²⁻]

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What time is it in California when its 7:00 a.m. in Florida?
bixtya [17]

Answer:

4:00 a.m.

Explanation:

The east coast is 3 hours ahead of the west coast

8 0
3 years ago
Read 2 more answers
Given a balanced chemical equation between H2SO4(aq) and KOH(aq) H2SO4(aq) + 2 KOH(aq) → K2SO4(aq) + 2 H2O(l) What volume (in mL
Lynna [10]

Answer:

48.84mL

Explanation:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the question:

nA = 1

nB = 2

From the question given we obtained the following information:

Ma = 0.43M

Va =?

Mb = 0.35M

Vb = 120mL

Using MaVa / MbVb = nA/nB, we can easily find the volume of the acid required. This is illustrated below:

MaVa / MbVb = nA/nB

0.43 x Va / 0.35 x 120 = 1/2

Cross multiply to express in linear form

2 x 0.43 x Va = 0.35 x 120

Divide both side by the (2 x 0.43)

Va = (0.35 x 120) /(2 x 0.43)

Va = 48.84mL

Therefore, the volume of H2SO4 required is 48.84mL

8 0
3 years ago
Read 2 more answers
What is the formula unit for a compound made from Li and Cl? (5 points)
Svetlanka [38]

Answer:

LiCl because the total negative charge on Cl is one.

Explanation:

Lithium has a charge of 1+ and Chlorine has a charge of 1-.

5 0
3 years ago
A 50.0 mL sample of waste process water from a food processing plant weighing 50.1 g was placed in a properly prepared crucible
RideAnS [48]

Answer:

TS (total solid, mg/L) = 57,174 mg/L

VS (volatile solid, mg/L) = 24,088 mg/L

Explanation:

First step to solve this problem is to know data and questions:

Data:

Sample volume = 50 mL

Sample weight = 50.1 g

P1 (weight empty crucible) = 17.1234 g

P2 (weight after drying a 103º in oven) = 19.9821  g

P3 (weight after incinatrion 550º) = 18.7777 g

Questions:

TS = ?  

VS = ?

Formula:

We need to use formulas to calculate total solid (TS) and volatile solid (VS), these are:

TS =\frac{(P2-P1)*\frac{1,000 mg}{1g} }{Sample volumen (L)}

VS = \frac{(P2-P3)*\frac{1,000 mg}{1g} }{Sample volume (L)}

We have to transform mL to L so we will divide mL by 1,000 the sample volume:

Sample Volumen (L) = 50 mL * \frac{1L}{1,000 mL} = 0.05 L

In the formula the value of 1,000 results by the convertion factor to transform grams to miligrams (we have to multiplie by 1,000)

Now we need to replace data on previous formulas and we will get TS and VS expressed in mg/L:

TS = \frac{(19.9821 g-17.1234g)*\frac{1,000 mg}{1g} }{0.05L} = 57,174mg/L

VS = \frac{(19.9821g-18.7777g)*\frac{1,000mg}{1g} }{0.05L}=24,088 mg/L

We divide TS and VS formula by sample volume because the exercise is asking us to express the results in mg/L.

4 0
3 years ago
1. By means of orbital diagrams, write down the
Dvinal [7]

Answer:

a) 1s22s22p63s1

b) 3s² 3p¹

c) 1s22s22p63s23p3

d) 3s² 3p⁵

e) 3s2

f) 1s22s22p63s23p2

g) 1s22s22p63s23p4

h) 3s² 3p⁶

3 0
3 years ago
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