Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.
The freezing rain falls and solidifies on a wire fence as the rain is changing from a liquid to a solid state by withdrawing thermal energy, ultimately resulting in freezing.
Molar mass H₃PO₄ = 98.0 g/mol
1 mole ----- 98.0 g
? mole ------ 30.0 g
moles = 30.0 * 1 / 98.0
= 0.306 moles
hope this helps!
Answer:
1.0 L
Explanation:
Given that:-
Mass of 
= 
Molar mass of = 64.099 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:-
1 mole of on reaction forms 1 mole of 
0.0396 mole of on reaction forms 0.0396 mole of
Moles of = 0.0396 moles
Considering ideal gas equation as:-
where,
P = pressure of the gas = 742 mmHg
V = Volume of the gas = ?
T = Temperature of the gas = ![26^oC=[26+273]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B26%2B273%5DK%3D299K)
R = Gas constant = 
n = number of moles = 0.0396 moles
Putting values in above equation, we get:
<u>1.0 L of acetylene can be produced from 2.54 g .</u>
