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3 years ago

If f(x)=2x and g(x)=x^2 -1, which statement is true?

Mathematics

1 answer:

choli [55]3 years ago

8 0

Answer: D

<u>Step-by-step explanation:</u>

f(x) = 2x g(x) = x² - 1

f(g(x)) = 2(x² - 1)

= 2x² - 2

g(f(x)) = (2x)² - 1

= 4x² - 1

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An investor bought 40 shares of ABC corporation's stock at $80 a share. Two weeks later, the investor receives notice that the c

Eva8 [605]

<span>The correct answer is C: 80 shares of the stock and the price of each share is $40.</span>

8 0

2 years ago

A 50-foot ladder leans against a wall, as shown in the figure below. If the base of the ladder is 30 feet away from the wall, ho

notka56 [123]

50^2 + 30^2 = x^2

2500 + 900 = x^2

3400 = x^2

x = sqrt(3400)

x = 58.31

height is 58.31 feet ( round answer as needed)

4 0

3 years ago

Destiny can run one-eighth of a mile in three-quarters of a minute, and she can walk one-quarter of a mile in 4 minutes. How man

yarga [219]

Answer:

a) Destiny can run 1 mile is 6 minutes.

b) Destiny can walk back 1 mile is 16 minutes.

Step-by-step explanation:

The running rate of Destiny is

$(\frac{1}{8}) \textrm{mile in} (\frac{3}{4}) \textrm{minutes}$

So, she runs 1 mile in $8 \times (\frac{3}{4} )\textrm{minutes}$

= 6 minutes

Hence, Destiny can run 1 mile is 6 minutes.

The walking rate of Destiny is

$(\frac{1}{4}) \textrm{mile in} 4 \textrm{minutes}$

So, she walks 1 mile in $4 \times (4 )\textrm{minutes}$

= 16 minutes

Hence, Destiny can walk back 1 mile is 16 minutes.

4 0

2 years ago

How many yards are in 45 inches

alexandr402 [8]

Answer:

1.25

Step-by-step explanation:

3 0

2 years ago

The sides of a triangle have lengths of x, x + 5, and 25. If the longest side is 25, which of the following values of x would ma

Amiraneli [1.4K]

In a right angle, the sum of the squares of the two shorter sides is equal to the square of the longest side.
Here, the longest side is 25, the shorter sides are x and x+5.

$x^2+(x+5)^2=25^2 \\
x^2+x^2+10x+25=625 \\
2x^2+10x+25=625 \ \ \ |-625 \\
2x^2+10x-600=0 \ \ \ |\div 2 \\
x^2+5x-300=0 \\
x^2+20x-15x-300=0 \\
x(x+20)-15(x+20)=0 \\
(x-15)(x+20)=0 \\
x-15=0 \ \lor \ x+20=0 \\
x=15 \ \lor \ x=-20
$

The length of a side must be a positive number, so x=15.
The answer is C.

6 0

3 years ago