We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
This is a guess but I think 24 hope I helped :))
Solution :
It says multiply 8 by 12 and then add 9
reading the sentence it is clear that priority is given to multiplication of 8 and 12 , once it is done then we would add 9 .
Let us first write multiplying 8 and 12 which makes it 8 x 12
the result is being add to 12 so we place 8x12 in parenthesis then add 12
which , makes it : ( 8x12) + 9
this matches to now of the given options so it is because multiplication is always given a priority comparing to addition so here parenthesis is not that important .
we can write it without parenthesis like : 8x12 +9
Answer is third option .
Answer:
-3/4^10
Step-by-step explanation:
you multiply powers 5 and 2
-3/4 ^10
Answer: 18
Step-by-step explanation: The formula for circumference is 2piR. Since 2piR = 36pi, you can cancel out the pi's which makes it 2r = 36. Divide by 2 on both sides and you get r = 18.
