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beks73 [17]
2 years ago
5

5+8-2x2 find all the possibilities for each problem by placing parenthesis in different places

Mathematics
1 answer:
erastova [34]2 years ago
6 0
(5+8) - 2x2
5+8 - (2x2)
That’s all I can say Bc you can’t do
5+ (8-2) x2
Or vice versa <3
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Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

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2 years ago
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Answer:

Here is your answer!

Step-by-step explanation:

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3 years ago
1. 201 - (-8) - 231 =<br><br><br> 2.632+(-196)-(-23) =
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Step-by-step explanation:

1) -22

2) -172.368

hope it helps

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What is your question?

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