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Alex Ar [27]
3 years ago
9

PLEASE HELP!!!!!!!!! WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

Part A: Yes; The first number in the sequence times 4

Part B: 1*4 =4, 2*4=8, etc.

Part C: 9*4= 36

Step-by-step explanation:

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Find the equation of the line parallel to 2y-3x= 4 and passing through the point (6,7)
frutty [35]

Answer:

We have equation of a line:

2y - 3x = 4 => y = (3/2)x + 4

The equation of the line that is parallel to above line and passes through the point (6, 7) would have form y = ax + b, and

a = 3/2

6a + b = 7

=> b = 7 - 6a = 7 - 6 x 3/2 = 7 - 9 = -2

=> The equation of that line: y = (3/2)x - 2

Hope this helps!

:)

7 0
3 years ago
What is the equation in point-slope form of the line passing through (1, 9) and (−1, 11)?
Ainat [17]
(1,9)(-1,11)
slope = (11 - 9) / (-1 - 1) = -2/2 = -1

there can be 2 answers for this...
y - y1 = m(x - x1)
(1,9)...x1 = 1 and y1 = 9
sub
y - 9 = -(x - 1) <== here is one answer

y - y1 = m(x - x1)
(-1,11)...x1 = -1 and y1 = 11
sub
y - 11 = -(x - (-1) =
y - 11 = -(x + 1) <== here is the other answer
6 0
3 years ago
Read 2 more answers
Help I WILL GIVE Brainiest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
kondor19780726 [428]

Answer:

b. infinite solutions

Step-by-step explanation:

-\frac{1}{2}x+\frac{1}{2}y=-1\\\\\textsf{subtract} \ -\frac{1}{2}y \ \textsf{from both sides:}\\\\\implies -\frac{1}{2}x=-1-\frac{1}{2}y\\\\\textsf{mulitply both sides by -2:}\\\\\implies x=2+y\\\\\textsf{subtract} \ y \ \textsf{from both sides:} \ x-y=2

Therefore, the graphs are the same.

If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations.

6 0
3 years ago
Read 2 more answers
Find p(2) for p(x) = x^4 + 3x^3 - 2x^2 - 4x + 1.<br><br> A. -7<br> B. -1<br> C. 25<br> D. 12
Otrada [13]
D:12 or B: -1 im hope good luck
5 0
3 years ago
Find the unknown side length. Write your answer in simplest radical form.
Eva8 [605]

Answer: 1. x= 20 units,   2. x= 5\sqrt{3} units    3. x= 4\sqrt{2} units.

Step-by-step explanation:

In a right triangle,

Hypotenuse^2= Perpendicular^2+Base^2  (Pythagoras theorem)

1. Hypotenuse = x , Base = 16, Perpendicular = 12

\Rightarrow\ x^2 =12^2+16^2\\\\ \Rightarrow\ x^2=144+256\\\\ \Rightarrow\ x^2=400\\\\ \Rightarrow\ x=\sqrt{400}=20

2. Hypotenuse = 14 , Base = 11, Perpendicular = x

\Rightarrow\ 14^2=x^2+11^2\\\\\Rightarrow\ 196=x^2+121\\\\\Rightarrow\ x^2=196-121\\\\\Rightarrow\ x^2 = 75\\\\\Rightarrow\ x=\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}

3.  Hypotenuse = 9 , Base = x, Perpendicular =7

\Rightarrow\ 9^2=x^2+7^2\\\\\Rightarrow\ 81= x^2+49\\\\\Rightarrow\ x^2=81-49\\\\\Rightarrow\ x^2=32\\\\\Rightarrow\ x=\sqrt{32}=\sqrt{16\times2}\\\\\Rightarrow\ x=4\sqrt{2}

5 0
3 years ago
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