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antoniya [11.8K]
3 years ago
15

What is the equation in point-slope form of the line passing through (1, 9) and (−1, 11)?

Mathematics
2 answers:
Ainat [17]3 years ago
6 0
(1,9)(-1,11)
slope = (11 - 9) / (-1 - 1) = -2/2 = -1

there can be 2 answers for this...
y - y1 = m(x - x1)
(1,9)...x1 = 1 and y1 = 9
sub
y - 9 = -(x - 1) <== here is one answer

y - y1 = m(x - x1)
(-1,11)...x1 = -1 and y1 = 11
sub
y - 11 = -(x - (-1) =
y - 11 = -(x + 1) <== here is the other answer
KengaRu [80]3 years ago
5 0
Use the point slope formula, y-y1=m(x-x1) to find the equation of the line.
y=-x+10
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3 years ago
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How do I solve this?
Ghella [55]

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The other end point is (-3,5)

Step-by-step explanation:

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For the mid point  (x,y)=(-1,1)

and (x_1,y_1)=(1,-3)

(x_2,y_2)=?

(-1,1)=((1+x_2)/2,(-3+y_2)/2)

(1+x_2)/2=-1\\\\1+x_2=-2\\\\x_2=-2-1\\\\x_2=-3

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(-3+y_2)/2=1\\\\-3+y_2=2\\\\y_2=2+3\\\\y_2=5\\

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