Find the equation of the line parallel to 2y-3x= 4 and passing through the point (6,7)
1 answer:
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Answer:
1)b
2)d)80/360×36π≈25.12cm²
4)d)32.5
5)c)135°
6)d)4π/3
Step-by-step explanation:
1) because as we know
Circle equation
=(x-a)²+(y-b)²=r²
=(x-5)²+(y+1)²=36 (given)
=(x-(+5))²+(y-(-1))²=6²
So
C(5,-1)and r=6
2)as we know area of sector
=Theta/360×πr²
=80/360×6²π
80/360×36×3.14
80/10×3.14
=25.12
4)to figure out 4 we have to separate the shape into 2 parts
First semi-circul
Second rectangle
So the parameter of the shape
=Circumference of semi-circul + the parameter of the rectangle
=[10π×½+2(10+3.4)]-10 (as the dashed line is not a part of parameter)
=[15.7+26.8]-10
=32.5
5)3π/4
3×180/4
540/4
135
6)240°
240°×π/180°
4π/3
