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Sever21 [200]
3 years ago
14

Find all the powers of 4 in the range 4 through 1,000

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
4 to the 1st is 4
4 to the 2nd is 16
4 to the 3rd is 64
4 to the 4th is 256

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What is the value of 36X negative Y over to when X equals three and Y equals -6
Rus_ich [418]

<u><em>Note:</em></u>

<em>Your question is a little unclear. But, from my understanding, I assume you may be asking the evaluation of the expression 36x - y when x = 3 and y = -6.</em>

<em>so I will solve based on my assumption which anyways would clear your concept.</em>

Answer:

The value of 36x - y when x = 3 and y = -6 will be: 114

Step-by-step explanation:

Given

Assuming the expression

36x - y

To Determine

Evaluate 36x - y when x = 3 and y = -6

Given the expression

36x - y

substitute x = 3 and y = -6 to evaluate the expression

36x-y= 36(3) - (-6)

            = 108+6

            = 114

Therefore, the value of 36x - y when x = 3 and y = -6 will be: 114

5 0
3 years ago
4-2(3+2) ²<br> 2.<br> Help me plz i need the help
strojnjashka [21]

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

Hope it will help you :)

5 0
3 years ago
Read 2 more answers
Assume that ∠A  is an acute angle. If sin A = 0.994, use a calculator to find the measure of ∠A to two decimal places.   The mea
Sedbober [7]
Basically, you are looking for the ARC SINE of .994 which is
 83.72 Degrees
You could also use an online calculator:
http://www.1728.org/trigcalc.htm


8 0
2 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
I NEED HELP ASAP!!!!! PLEASE
sasho [114]

Answer:

I think b, but I may be wrong

6 0
3 years ago
Read 2 more answers
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