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Marina CMI [18]
3 years ago
13

DUE IN 5 MINS PLEASE HELP

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

12

Step-by-step explanation:

you can pack one pack in 20 min

there are three 20 min in one hour

multiply three times the four hours and you get 12

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The auxiliary bookstore in the student center has one checkout counter where one employee operates the cash register. Customers
natima [27]

Answer and explanation:

Find attached

Both customers' arrival and service times follow exponential distribution. We have calculated the essential operating characteristics of this queuing system

8 0
3 years ago
Simplify and write answer in standard form.
mamaluj [8]

Answer:

x^3+8x^2+2x+1

Step-by-step explanation:

Combine like terms (terms with the same exponent).

x^3+(3x^2+5x^2)+(x+x)+1=x^3+8x^2+2x+1

"Standard form" means to list terms so the exponents go from high to low (descending order).

6 0
3 years ago
The low temperatures for one week in Scottsburg, IN are given below. What was the mean daily low temperature for the week? −7.9°
gogolik [260]
Your answer: -0.8

first you would add all of your temperatures together which would give you -5.6

then you would divide -5.6 by 7 because u have 7 numbers

which would give you your answer!

hope this helps, good luck!
7 0
3 years ago
Read 2 more answers
What is the lmc for 6 and 14
lana [24]

Answer:

The Lcm is 42/

Step-by-step explanation:

Least common multiple (LCM) of 6 and 14 is 42.

Hope that helped.

5 0
3 years ago
Read 2 more answers
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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