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Rudik [331]
3 years ago
9

Given the function f(x), whose graph is shown below, place the black draggable dot at the point that corresponds to f−1(−4).

Mathematics
1 answer:
astraxan [27]3 years ago
7 0

Answer:eyys

Step-by-step explanation:

yes

jdvimj

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If ten is no more than four times the sum of twice a number and three how do I write and work this for algebra
vagabundo [1.1K]
(2x+3)*4 is less than or equal to 10. For x, the number, you would get x is greater than or equal to -1/4.
7 0
3 years ago
Which of the following slopes of a line passes through points (2, 3) and (4,7) ?
serg [7]

Answer:

2

Step-by-step explanation:

slope = (difference in y)/(difference in x)

slope = (7 - 3)/(4 - 2)

slope = 4/2 = 2

Answer: 2

8 0
3 years ago
What is the measure for STU?
Vesna [10]
18q+18=180
-18. -18
18q=162
/18. /18
q=9
3q=27
8 0
3 years ago
Write the monomial in standard form. name it's coefficient and identify its degree.
Hunter-Best [27]

Answer:

Standard\ Form = {3n^2} m^{-2}

Step-by-step explanation:

Given

\frac{2}{3m^2n} * 4.5n^3

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

\frac{2}{3m^2n} * 4.5n^3

Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}

Split the numerator and the denominator

Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}

Multiply Like terms

Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}

Divide 9 by 3 to give 3

Standard\ Form = \frac{3 * n^3}{m^2 * n}

Divide n³ by n to n²

Standard\ Form = \frac{3 * n^2}{m^2 }

Split fraction

Standard\ Form = {3 * n^2} * \frac{1}{m^2 }

From laws of indices;

\frac{1}{a^n} = a^{-n}

Standard\ Form = {3 * n^2} * \frac{1}{m^2 } becomes

Standard\ Form = {3 * n^2} * m^{-2}

Multiply all together

Standard\ Form = {3n^2} m^{-2}

5 0
3 years ago
This is my question!<br> Please help answer!!!
svp [43]

The x and y coordinates of point S are increased by three to get to the midpoint.

(2,1) ----> (5,4)

To get to point t increase the coordinates by three again.

(5,4) -----> (8,7)

answer: (8,7)

6 0
3 years ago
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