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oksian1 [2.3K]
2 years ago
10

A 45000 car depreciates 12% each year how much does the car decrease by the end of the 1st year

Mathematics
1 answer:
emmasim [6.3K]2 years ago
3 0

Step-by-step explanation: It would take off a total of 5.4% which equals to 5,400 because 12% of 45000 is 5,400

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Answer:

Step-by-step explanation:

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2 years ago
You push your younger sister on a swing one time and then allow your sister to
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Answer:

My sister will swing the total distance = 40 feet

Step-by-step explanation:

On the first swing my sister travels a distance of 8 feet.

In every successive swing she travels 80% of the distance of the previous distance.

So the sequence formed by the distance traveled in every swing will be a geometric sequence.

First term of the sequence 'a' = 8 feet

common ratio 'r' = 0.80

Since this sequence is an infinite geometric sequence,

Sum of this sequence = \frac{a}{(1-r)}  [Since r < 1]

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7 0
2 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

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t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

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We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

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N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Which numbers are the extremes of the proportion shown below?
prisoha [69]
A


Mark brainliest please mark



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3 0
3 years ago
Read 2 more answers
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hjlf

Answer: The size and shape will only change when the transformation being made to the figure is a dilation. Since it is only being translated, its image and preimage are still congruent in size.

Step-by-step explanation:

4 0
3 years ago
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