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oksian1 [2.3K]
3 years ago
10

A 45000 car depreciates 12% each year how much does the car decrease by the end of the 1st year

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Step-by-step explanation: It would take off a total of 5.4% which equals to 5,400 because 12% of 45000 is 5,400

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Aurora Springs and Glendale are 48 miles apart. You would take how much one inch is and multiply it by 4 to get how much 4 inches is. so 12*4=48
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The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.D1d2, where d1 and d2 are the l
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Answer:

d1=2A/d2

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Step-by-step explanation:

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2Ad₁

Given:

A=1/2(d1*d2)

Multiply both sides by 2

We have,

2A=d1*d2

Divide both sides by d2

2A/d2=d1*d2/d2

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Therefore, d1=2A/d2

Similarly, from the previous equation

2A=d1*d2

Divide both sides by d1

2A/d1=d1*d2/d1

2A/d1=d2

Therefore,

d2=2A/d1

Options

2. d₁= 2A/d₂

4. d₁= 2A/d₂

7 0
3 years ago
Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k
Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

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Step-by-step explanation:

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x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

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Answer:

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