Answer:
It enters the citric acid cycle and associates with a 4-carbon molecule, forming citric acid, and then through redox reactions regenerates the 4-carbon molecule.
Explanation:
Acetyl-CoA(2C) associates with oxalacetate(4C) to form citric acid(6C). Then through redox reactions, CO2 molecules result from decarboxylation (COOH becomes R-(R1)CH-R2). And through dehydrogenation H2 molecules are incorporated in NADH+ in FADH2, resulting in the 4-carbon molecule at the beginning (oxalacetate). That's why it's called a cycle(Kreb's cycle or citric acid cycle)
I think it’s B, sorry if I’m wrong
Answer:
it is w
Explanation:
i have done a similar question
If dominant allele = p, and recessive allele = q,
and p+q = 1, then:

So if 75% have the p, then p^2 = homozygous dominant

And if the other 25% have the q, the q^2 = homozygous recessive

Now those remaining MUST be the heterozygous, thus 2pq are those:
2pq = 2(.75)(.25) = .375
Therefore homozygous dominant are 56.3% and heterozygous are 37.5%