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olganol [36]
3 years ago
8

Please help with math show your work

Mathematics
2 answers:
zzz [600]3 years ago
5 0
<span><span><span><span><span>(5)</span><span>(<span>−3</span>)</span></span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span><span>=<span><span><span><span>−15</span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span><span>−15</span>−<span>(<span>−12</span>)</span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span>−3</span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span>(<span>−9</span>)</span></span></span><span>=<span>3</span></span>
Katarina [22]3 years ago
4 0
The answer is six but i entered this in calculator so no work
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35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa
Tatiana [17]

Answer:

1450-2.0\frac{30}{\sqrt{25}}=1450-12    

1450+2.0\frac{30}{\sqrt{25}}=1450+12    

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

\bar X=1450 represent the sample mean for the SAT scores

\mu population mean (variable of interest)

s^2 = 900 represent the sample variance given

n=25 represent the sample size  

Solution

The confidence interval for the true mean is given by :

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The sample deviation would be s=\sqrt{900}= 30

The degrees of freedom are given by:

df=n-1=2-25=24

The Confidence is 0.954 or 95.4%, the value of \alpha=0.046 and \alpha/2 =0.023, assuming that we can use the normal distribution in order to find the quantile the critical value would be z_{\alpha/2} \approx 2.0

The confidence interval would be

1450-2.0\frac{30}{\sqrt{25}}=1450-12    

1450+2.0\frac{30}{\sqrt{25}}=1450+12    

And the best option would be:

c. 1450 +/- 12

3 0
3 years ago
Use the formula P=21+2w to find the width of a rectangle when the length is 18cm and perimeter is 48 ..
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Answer:

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Step-by-step explanation:

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48=36+2w

12=2w

w=6

checking;

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48= 36+12

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Answer:

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Step-by-step explanation:

Hope this helps!

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Step-by-step explanation:

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MariettaO [177]
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xy <=> x + y
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