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AnnZ [28]
2 years ago
6

Which Equation represents the line passing through points a and C on the graph below

Mathematics
1 answer:
zimovet [89]2 years ago
6 0

Answer:

D!!

Step-by-step explanation:

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What x what gives me 49 but when you add it it gives me 14
Scilla [17]
7 because 7 x 7 is 49 but if you add 7 and 7 it gets to 14 7 is the answer
so if you do a different number you will be wrong

3 0
3 years ago
Solve this please quickly
Volgvan

Answer:

1. m∠B=110°

2. 560 cm3

3. Numerical data

4. 2000 cm3

5. 50%

Step-by-step explanation:

1. The explanation of part 1 is given in the attachment.

2. Given dimensions : 10 cm, 8 cm, and 7 cm.

Let Length of cuboid =10 cm

breadth/width of cuboid  =8 cm

height of cuboid = 7cm

Volume of cuboid = length *width* height

=( 10 *8*7) cm3

=(560) cm3

3. Age, Birth date  and weight are the types/examples of "<u>Numerical Data"</u> because these all are describe in terms of numeric values.

4. 1 liter = 1000 cm3   or   1 cm3 = 0.001 liter

1.5 liters =(1.5*1000) cm3 = (15*100) =1500 cm3

1 dm3 =1000 cm3

0.35 dm3 = (0.35*1000) cm3 = (35*10) cm3 =350 cm3

Given expression: 1.5 litre + 0.35 dm3 + 150 cm3 = <u>               </u> cm3

1500 cm3 + 350 cm3 +150 cm3 = <u>2000</u> cm3

5. If A=(1/2)B, then B : A = <u>50</u> %

Ratio: B : A

B : (1/2) B

1: (1/2)

50 % (The value of A is half of the value of B)

Download docx
6 0
3 years ago
HELP ASAP!! What is the average rate of change between x = -3 and x = 4 for the equation y = 8x2?
Llana [10]

Answer:

x=-3\\y=8(-3)^2\\y=8(9)\\y=72

x=4\\y=8(4)^2\\y=8(16)\\y=128

128-72=56

average rate of change is 56

Step-by-step explanation:

Plz let me know if im right

3 0
2 years ago
Number 7 using algorithm
aniked [119]
Sorry it says plus but its times

6 0
3 years ago
Which function is an odd function?
hjlf
A function is odd if:
f ( - x ) = - f ( x )
A ) f ( - x )= 0.8 ( - x ) ^3 = - 0.8 x^3 = - f ( x )
Answer: A ) f ( x ) = 0.8 x^3 is an odd function. 
Functions B ) and C ) are even and D) is neither even nor odd.
8 0
3 years ago
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