Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.
<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.
The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:
- 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1
Mass of 2 moles of ammonia = 2 * 17 = 34 g
Mass of 1 mole of (NH₄)₂SO₄ = 132 g
Mass of ammonia required = 34/132 * 2.40 × 10⁵ kg
Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.
In conclusion, the mole ratio is used to determine the mass of ammonia required.
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A theory fits all three of these descriptions. you can test, predict, and prove or disprove a theory. hope this helps!
Answer:
Explanation:
The first thing we need to know is that the amino acid of tyrosine has an aromatic ring within its structure.
Also, recall that aromatics hydrocarbons are considered to be unsaturated and non-polar.
So, since like dissolve like. Then, The non-polar character of tyrosine is enhanced by its aromatic ring. As a result, Tyrosine amino acid is much more soluble in less polar solvents like methanol and ethanol than in moderate highly polar water.
From the given information:
Since water is a very polar solvent, and tyrosine amino acid is not particularly polar, it is just barely soluble in it.
In addition to the aforementioned, peptides are strongly polar in nature. However, as the amount of tyrosine amino acids in a peptide increases, the region of the non-polar portion of the peptide increases (owing to the rise of the aromatic ring), and thus the non-polar value of the peptide will also rise. And this non-polar nature of peptide will make them more soluble in non-polar solvent and decrease its solubility in water (because water is polar in nature). And since peptides are non-polar, they would be more soluble in non-polar solvents and have less solubility in water.