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kramer
4 years ago
14

12 POINTS!! Which step would help a student find the molecular formula of a compound from the empirical formula?

Chemistry
1 answer:
pishuonlain [190]4 years ago
7 0
Is the C because the mass in the compound is correct
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What hypothesis led to the discovery of the proton?
Lana71 [14]

When a neutral hydrogen atom loses an electron, a positively-charged particle should remain.

4 0
3 years ago
Read 2 more answers
Two common uses for electromagnets are _____.
Novosadov [1.4K]

Two common uses for electromagnets are _producing strong magnetic fields_& __electrical switches_.

Explanation:

An electric current can turn a ferromagnetic material temporarily magnetic using Faraday's principle, if the wire carrying the current is wound in coils around the ferromagnetic material. When the electric current is turned on the ferromagnetic material, such as iron, becomes magnetic but loses the magnetism when the current is switched off. This application can be used in a junkyard where a crane with a ferromagnetic arm can lift scrap cars from one point and dump them is a scrapper.

An electromagnet switch can also be applied in the switching on and off of a larger current. These are called relay switches. When the smaller current is turn on, it magnetizes a ferromagnetic material. The magnet then attracts another metal that is attached to a contact arm of a switch. The attraction results in the closing of a switch  of a larger current. When the smaller current is switched off, the loss of magnetism causes the metal with the contact arm to open the larger switch.

Learn More:

For more on electromagnets check out;

brainly.com/question/12350331

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#LearnWithBrainly

6 0
3 years ago
What is the Lewis structure of CH3F
Yanka [14]
I need help as well?!
8 0
4 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
A sample of helium gas has a pressure of 1.20 atm at 22.0 C. At what Celsius temperature will the helium reach a pressure of 2.0
Anarel [89]

Answer: 36.6°C

Explanation:

Given that,

initial pressure of helium (P1) = 1.20 atm

Initial temperature (T1) = 22.0°C

Final temperature (T2) = ?

Final pressure of helium (P2) = 2.00 atm

Since pressure and temperature are given while volume is constant, apply the formula for pressure's law

P1/T1= P2/T2

1.20 atm / 22.0°C = 2.00 atm / T2

Cross multiply

1.20 atm•T2= 2.00 atm•22°C

1.20 atm•T2= 44 atm•°C

Divide both sides by 1.20 atm

1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm

T2 = 36.6°C

8 0
4 years ago
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