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3 years ago

Why is a bunsen burner flame hotter than a normal gas flame

1 answer:

7 0

While the normal gas flame can only produce a “operating” to “light blue” type of flame, the Bunsen burner can at least yield three types of flame. Consequently, the following: 

Operating flame – which is yellow/orange in color, near 300° C. · 

Blue flame – can be imperceptible under normal lighting conditions, near 500° C. The typically used laboratory type of flame. ·

Roaring-blue flame – forms a triangular shaped in the center of the flame normally light blue in color and interestingly, it’s a sound-producing flame. Heat is near to 700° C. 

Imagine with this three kinds of flame produced and a Bunsen burner creates compared to a simple normal gas flame. In sense, the roaring-blue flame proves evident as to why Bunsen burner is hotter hence, the amount of heat it makes (700°C) it makes.

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A. An element with the valence electron configuration 5s1 would form a monatomic ion with a charge of ______In order to form thi

vfiekz [6]

Answer: A. An element with the valence electron configuration 5s1 would form a monatomic ion with a charge of Answer: +1. In order to form this ion, the element will Answer: lose electron(s) from/into the 5s subshell(s).

Explanation:

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3 years ago

Consider the following elementary reaction:

Marat540 [252]

Answer:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

Explanation:

Hello!

In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:

$r=-k_1[NO]+k_{-1}[N_2O_2]$

However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:

$0=-k_1[NO]+k_{-1}[N_2O_2]$

Which can be also written as:

$k_1[NO]=k_{-1}[N_2O_2]$

Then, we solve for the concentration of NO to obtain:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

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8 0

3 years ago

One gram of Sn was electroplated from a SnCl, solution in 30 minutes. What was the current used?

Andrews [41]

Answer:

0.903 A

Explanation:

We have given mass of Sn = 1 gram

Time t=30 minutes=30×60=1800 sec

According to Faraday law m=zit

Where z is electron chemical equivalent

z is calculated by $z=\frac{atomic\ mass}{nF}$ where n is number of element and F is Faraday constant

So $z=\frac{atomic\ mass}{nF}=\frac{118.71}{2\times 96500}=0.000615$

So $1=0.000615\times i\times 1800$

i =0.903 A

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4 years ago

Look up the densities of the elements

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Explanation:

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