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Nutka1998 [239]

2 years ago

11

Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?

2 answers:

snow_lady [41]2 years ago

3 0

The converse alternate exterior angles theorem justifies why lines j and k must be parallel.

The converse alternate exterior angles theorem states that if two lines are cut by a transversal so that alternate exterior angles are congruent, then the lines are parallel.

prisoha [69]2 years ago

3 0

Answer:

D

Step-by-step explanation:

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Which expression lists the three consecutive integers starting with a number x? A. x, x + 2, x + 4 B. x + 1, x, x + 2 C. x – 1,

Vika [28.1K]

Consecutive integers are like 1, 2, and 3. They are in a row. Think about plugging numbers in for x. 1 and 1+2 are not consecutive, so A is not the answer. B and C don't start with x, so they aren't the answer. That leaves D, because it starts with x, then goes to x+1, and then to x+2. These are consecutive, because if x was 1, it would be 1, 2, 3.

The answer is D.

I hope this helps :)

3 0

3 years ago

Read 2 more answers

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago

G(t)= t^2 + 3<br> h(t) = 4t – 3<br> Find (g · h)(-1)

MArishka [77]

Answer:

fifty-two. Explanation: g(h(−1 ))=g(x). x=h(−1)=4(−1)−3=−4−3=−7. g(x)= g(−7)=72+3=49+3=52.

6 0

3 years ago

You want to change your cell phone service. The new company charges $40 per month for cell phone use. There is a one-time start-

faltersainse [42]

25+40*t=c
T=time,c=cost over time

4 0

3 years ago

Read 2 more answers

Please help me I really need help

sergey [27]

Answer:

both are done

look at picture

1. 13/36

2. 3/16

6 0

2 years ago